A satellite close to the earth is in orbit above the equator with a period of revolution of 1.5 hours. If it is above a point P on the equator at some time, it will be above P again after time
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(b, c)
ω S = 
, ω E = 
ω west to east = 2 π 
T west to east = 
= 1.6 hours
Similarly
ω east to west = 2 π 
T east to west = 
hours
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